I have always been shit at algebra.
I have dyscalculia (for math problem, counting coins) and dyspraxia (hard time with spatial / time localization, which is probably why I cannot read a map ? ) Someone asks me to spot a mountain on a map? I can't do it. I can see a mountain on a PICTURE. But map? can't.
I can't even read a simple map or count my coins properly (i also suck at maths, even simple ones).
I can't even read a simple map or count my coins properly (i also suck at maths, even simple ones).
Paid for glowing award
Not only can i not count my coins, basic simple maths (divide, multiplicate), i also can't understand distances (like if someone tells me "It is 2 hours by car from here to over there" I understand it better than if they said "It is 500km by car."
Kilometres Can't understand those. I don't know what's a 100m distance nor a km I have to speak with "hours" ( 1 hour from here to there by car, etc...) if someone speak with "hours" instead of kilometres, I understand easier.
I also can't even lace my shoe properly. I can make the tie with my shoes laces, but usually the tie goes away on its own after walking for just 5 min . My doctor told me its because I have a "slow motor skills. ( a nicer term that calling me a imbecile )
Kilometres Can't understand those. I don't know what's a 100m distance nor a km I have to speak with "hours" ( 1 hour from here to there by car, etc...) if someone speak with "hours" instead of kilometres, I understand easier.
I also can't even lace my shoe properly. I can make the tie with my shoes laces, but usually the tie goes away on its own after walking for just 5 min . My doctor told me its because I have a "slow motor skills. ( a nicer term that calling me a imbecile )
Let f be a Boolean function. Prove that exactly one of f and its negation can be build by applying AND and IMPLIES to the input variables.
Zhegalkin polynomials
prove that the Boolean function that can be build using AND and IMPLIES are exactly the same as those that can be build using AND and IFF
What is 105÷5045000 because the calculator gives random numbers and it makes no sense
maths are for gays anyways
I can't believe this thread is still pinned kek.
D
isn't that false? what if a=b=c=1?
if a = b = c = 1, then 1/a + 1/b + 1/c = 1/1 + 1/1 + 1/1 = 1 + 1 + 1 = 3 which is not strictly less than 1
cant believe op is gone
Did you lurk for a long time?
Here's a SAT problem I remember. If a, b, c, and d are all distinct integers such that (a−1)(b−1)(c−1)(d−1) = 9, what is the value of a+b+c+d? No cheating hehe
Looking at the divisors of 9 it's plain to see that the four factors must be ±1 and ±3. Ergo a + b + c + d = 4
My answer: 8.
How I got my answer:
I started by finding all possible factorizations of 9 into four distinct integers; 1 , − 1 , 3 , − 3 1,−1,3,−3. I add the numbers, and the final result came to 8.
Oh shit, missed the step where I was supposed to add the actual values of the variables. 4 in that case
Yes 4 is correct. SAT problems are intentionally tricky in that way.
Here's an SAT problem I missed. If a circle of radius 2 rolls around the outside of a square of side measuring 8, with the circle always remaining in contact with the square, what is the distance traveled by the center of the circle in one trip around the square? See diagram, the arrow is the direction the circle is rolling in:
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the path traced by the centre is exactly the locus of points distance 2 away from and outside the square. this locus consists of four lines of length 8 parallel to the sides of the square and four quarter circles with radii of 2 "rounding the corners". All in all, the perimeter of the locus is equal to the perimeter of the original square + the circumference of a circle with radius 2 -- i.e., 4*8 + 2*pi*2 = 32 + 4*pi.
I'm altmaxxing
Yes correct
OK I'm kinda proud of this problem, I came up with it myself. If (m-100)(n-200)(o-500)(p-544) = 2025, and m, n, o, and p are different positive integers, what is m+n+o+p? No cheating, no AI 
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