-(Lim x--->0 (| 2x - 1| - | 2x + 1|)/x)
16, 90.6̅
Correct
another dAY another GrAY
he said no cheating. cheating is not helping you get smarter, cheating is lying to people, and cheating is wrong. you also clearly didnt read his original message that said "no cheating" because otherwise you would have known. The first two rules to math are 1. DONT CHEAT!!!!1 and 2. Read the problem alllll the way through. Just going off of this, you probably cheat in other areas of life too, dont you? Infact, this is why you are an incel. If you hadnt cheated, you might have turned out differently. However, you can still change your future! Thats right, its not too late!!! If you start reading problems the whole way through and stop cheating, you will not be an incel anymore!! Be smarter my friend
If the coefficient of x3 and x4 in the expansion of (1+ax+bx2)(1−2x)18 in powers of x are both zero, then (a,b) is equal to
Click hereto get an answer to your question ✍️ if the coefficient of x3 and x4 in the expansion of 1axbx212x18 in powers ofwww.toppr.com
Wtf are you talking about?
i could be wrong but i dont think there is anything more you can do with this.
YEAAAAAAAAAAAAAAH
Seems to be true for all 999 integer values. Let's se what else we can add
I've written it wrongly, it should be: For how many values of x is f(x) = x(raised to the floor function of x) a positive integer less than 1000
Trying to guess something besides 1,2,3,4
For every real value of x between 0 and 1 f(x) would be 1. Which is less than 1000. So the answer is infinity?
Indeed, X needs to be equal or greater than 1, though I'm struggling to find the original problem
In that case I can only think of 1,2,3,4. For any other non integer value, f(x) would be non integer.
It's all values of x(raised to floor), such that f(x) is an integer.
Nice catch. So all integer sqroots btw 2 and 3. 5,6,7,8 . All integer cube roots between 3 and 4. 64-27-1= 36. All fourth roots btw 4 and... Whatever. 625-256-1=368
Correct
Unless I'm making a mistake this is coming out to be a pretty big number
Correct
You are forgetting a bracket
What kinda question is this. I don't see a single solution in that range
Correct
BruhCorrect
| Unintelligent_Anon Join Date: 2016-02-24 Post Count: 361 | #185501144Wednesday, March 16, 2016 11:07 PM CDT Greetings, Off-Topic. On this particular occasion, I have decided to have an entertaining discussion with all of you by composing a simple game based on logical-reasoning. Firstly, while utilizing mathematics, we have objective statements such as "x = 5" Those particular type of statements are properly known as "predicates", given that they equate to either the Boolean values of true and/or false. within the above premise, it merely defines the quantity that variable 'x' represents. Therefore, it is "true" predicate. Although I used "x = 5", we could use symbolic notation such as this: E(x) = 5 Where uppercase "E" refers to the word "Equal", and the input variable 'x' receives the quantity described on the opposite side of the "=" operand. --------------------------------------- Recognizing the above objective explanation, the goal of the game is rather basic: to derive logical expressions to be interpreted by other users. I have devised a minimal list of logical symbols below: "-->" - The logical "if-then" operator. "If certain cookies are delicious, then some grapes are bluish"(Note that the premise predicate and the conclusion predicate do not necessarily need to be related. They merely need to have an obtainable Boolean value. '~' - The logical "NOT" operator. It merely negates "true"/"false" Boolean predicates into the opposite Boolean value. ~"I decided to traverse the area" becomes "I decided not to traverse the area." "^" - The logical AND operator. "(1+1 = 2) ^ (2 + 2 = 4) --> (5 + 5) == 10", which is true, given that "1 + 1 = 2 ^ 2 + 2 = 4" are both (true ^ true) respectively. Disregarding all of the other logical operators for the current moment, this is a sample expression that I have devised below: Suppose that we have variables 'a' and 'b': a = 100 b = 50 Firstly, let us define a predicate to determine whether the first value is a factor of the second value: R(a,b) = (a % b) This will retrieve the remainder of the division operation "a/b", using the difference between 'a' and 'b' as a referent. Likewise, R(b,a) would also retrieve the remainder of the division operation "b/a", using the difference between 'b' and 'a' as a referent. If I had an expression such as this: (R(a,b) = 0) ^ (R(b,a) = 0) It would be an expected case of a true/false pair. This is due to the mere fact that the (100 % 50) does not have a remainder, whereas (50/100) does indeed have a remainder of fifty itself. Hopefully the above descriptions provides a rather wholesome and otherwise precise discussion involving mathematical logic. |
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