SuicideFuel Problem

[trying to ascend]

Consider the real function f, defined by f(x) = - 2/x and two circumferences C1 and C2, with centers in the origin. It's known that C1 is tangent to the graphic of F, and that the point of X = -1/2 belongs to both C2 and the graphic. Given that, what's the size of the annulus defined by C1 and C2?

 

[Pancakecel]

Deez nuts

 

[trying to ascend]

Deez nuts

Answer for the problem?

 

[Deleted member 39372]

Consider the real function f, defined by f(x) = - 2/x and two circumferences C1 and C2, with centers in the origin. It's known that C1 is tangent to the graphic of F, and that the point of X = -1/2 belongs to both C2 and the graphic. Given that, what's the size of the annulus defined by C1 and C2?

it's a scandal that we don't learn how to do maths in english at school.

 

[FamilyGuy1999]

Deez nuts

 

[TallCelFag]

Is this high school or college problem?

 

[based_meme]

Is this high school or college problem?

College. OP wants us to do his work for him.

 

[TallCelFag]

College. OP wants us to do his work for him.

 

[trying to ascend]

Is this high school or college problem?

High school

 

[trying to ascend]

College. OP wants us to do his work for him.

I just post the ones I can't solve, it's not about lazyness

 

[iceandblood]

Vc ainda tá no ensino médio?

 

[trying to ascend]

Vc ainda tá no ensino médio?

Sim

 

[mentally lost cel 1]

Consider the real function f, defined by f(x) = - 2/x and two circumferences C1 and C2, with centers in the origin. It's known that C1 is tangent to the graphic of F, and that the point of X = -1/2 belongs to both C2 and the graphic. Given that, what's the size of the annulus defined by C1 and C2?

What the fuck is this ? The answer is (-1/2)x2xpi

Your question seems weird and out

 

[trying to ascend]

What the fuck is this ? The answer is (-1/2)x2xpi

Your question seems weird and out

No, it's not.

How you came with that result?

 

[mentally lost cel 1]

No, it's not.

How you came with that result?

Then it’s (-1/2)xpi

 

[mentally lost cel 1]

No, it's not.

How you came with that result?

Isn’t it a half circle from the origin?

 

[trying to ascend]

Then it’s (-1/2)xpi

-1/2 is not the radius

 

[mentally lost cel 1]

No, it's not.

How you came with that result?

I probably didn’t understand the question lol

 

[mentally lost cel 1]

-1/2 is not the radius

It’s pi, sorry for my dumbo brain lol

 

[mentally lost cel 1]

The answer is pi number

 

[mentally lost cel 1]

Or 2pi

 

[trying to ascend]

I probably didn’t understand the question lol

You have two circles, both with centers in the origin, and a function (x) -2/x

The function is tangent to one circle and it touches the other circumference when X = -1/2.

Which part didn't you understand?

 

[trying to ascend]

The answer is pi number

No, you don't know the radius, so you can't come up with it

 

[mentally lost cel 1]

You have two circles, both with centers in the origin, and a function (-2/x).

The function is tangent to one circle and it touches the other circumference when X = -1/2.

Which part didn't you understand?

Answer is 7pi

 

[trying to ascend]

Answer is 7pi

No

 

[mentally lost cel 1]

No

It is

 

[trying to ascend]

It is

Demonstrate why

 

[the.oracle]

my iq is too low for this

 

[Rhaast]

it's a scandal that we don't learn how to do maths in english at school.

 

[NoLooksNoLife]

Deez nuts

 

[falloutpilled]

The answer is (-1/2)x2xpi

Then it’s (-1/2)xpi

The answer is pi number

Or 2pi

Answer is 7pi

 

[trying to ascend]

WHAT'S THE SOLUTION?

 

[uo89997]

idk