Welcome to Incels.is - Involuntary Celibate Forum

Welcome! This is a forum for involuntary celibates: people who lack a significant other. Are you lonely and wish you had someone in your life? You're not alone! Join our forum and talk to people just like you.

Marvel Rivals is pretty dull

starystulejarz

starystulejarz

30+ years old khfl slavcel neetcel (13yrs+) virgin
★★★★★
Joined
May 2, 2018
Posts
13,357
It looks better than overwatch, and run 10x worse thanks to UE5 trash engine, DLSS/FSR/Xess is now mandatory to reach over 60fps on low.
You have more variety than OG Overwatch with over 30 characters and abilities but game objectives completely ruin it since they are as boring and limited in variety as in Overwatch which was a downgrade from TF2, where is the originality? Gameplay is just boring, stale and matches last for just 5-10mins.
Monetization is actually good since all characters are free, and first BP cost just $5 with 5 mediocre skins :lul: , next one will probably be sold for $10 with even more mediocre skins :feelsPop:, you get 300 currency back with your 490 currency BP required to buy BP.
As starting f2p player you don't see any kind of progression so you may as well ask yourself what's the point of playing after getting bored of gameplay loop and i'm already bored after 6 matches even tho i would like to experiment with more characters (they are fun). Time to try out GF2
There are not much else to talk about the game except that it has rank matches, it will be obviously heaven for a sweatlords, and that some objects can be destroyed but they never affect the gameplay just look cool.
 
20241206 025342
 
6362(38&3$33)373737373737
∫0∞e2πi+Γ(12)ζ(−3)3⋅cosh⁡(ln⁡x2+π3)sinh⁡(x+tan⁡−1(ex))dx=∑n=1∞(5+i)2n⋅(n2⌊πn⌋)Γ(n+1)\int_{0}^{\infty} \frac{\sqrt[3]{e^{2\pi i} + \Gamma\left(\frac{1}{2}\right) \zeta\left(-3\right)} \cdot \cosh\left(\ln x^2 + \frac{\pi}{3}\right)}{\sinh\left(\sqrt{x} + \tan^{-1}(e^x)\right)} dx = \sum_{n=1}^{\infty} \frac{\left(\sqrt{5} + i \right)^{2n} \cdot \binom{n^2}{\lfloor \pi n \rfloor}}{\Gamma(n+1)}
 
∫0∞e2πi+Γ(12)ζ(−3)3⋅cosh⁡(ln⁡x2+π3)sinh⁡(x+tan⁡−1(ex))dx=∑n=1∞(5+i)2n⋅(n2⌊πn⌋)Γ(n+1)\int_{0}^{\infty} \frac{\sqrt[3]{e^{2\pi i} + \Gamma\left(\frac{1}{2}\right) \zeta\left(-3\right)} \cdot \cosh\left(\ln x^2 + \frac{\pi}{3}\right)}{\sinh\left(\sqrt{x} + \tan^{-1}(e^x)\right)} dx = \sum_{n=1}^{\infty} \frac{\left(\sqrt{5} + i \right)^{2n} \cdot \binom{n^2}{\lfloor \pi n \rfloor}}{\Gamma(n+1)}
Excuse Me Reaction GIF by One Chicago
 
lim⁡x→∞∫−∞∞∏n=1∞Γ(ζ(3)+n2esin⁡(πx))⋅cosh⁡(ln⁡(x3π2+n5))∑k=1∞(ekk!+sin⁡(ζ(2)))kΓ(k+1)⋅e−αx2dx=∑j=1∞(−1)j⋅ln⁡j!(ej57+∏p=1jΓ(p3))cos⁡(πj)+ej28\lim_{x \to \infty} \int_{-\infty}^{\infty} \frac{\prod_{n=1}^{\infty} \Gamma\left(\frac{\zeta(3) + n^2}{e^{\sin(\pi x)}}\right) \cdot \sqrt{\cosh\left(\ln\left(\frac{x^3}{\pi^2} + \sqrt[5]{n}\right)\right)}}{\sum_{k=1}^{\infty} \frac{\left(e^{k^{k!}} + \sin\left(\sqrt{\zeta(2)}\right)\right)^k}{\Gamma(k+1)}} \cdot e^{-\alpha x^2} dx = \sum_{j=1}^{\infty} \frac{\left(-1\right)^j \cdot \ln^{j!}\left(e^{\sqrt[7]{j^5}} + \prod_{p=1}^{j} \Gamma(p^3)\right)}{\cos\left(\frac{\pi}{j}\right) + \sqrt[8]{e^{j^2}}}
 
lim⁡x→∞∫−∞∞∏n=1∞Γ(ζ(3)+n2esin⁡(πx))⋅cosh⁡(ln⁡(x3π2+n5))∑k=1∞(ekk!+sin⁡(ζ(2)))kΓ(k+1)⋅e−αx2dx=∑j=1∞(−1)j⋅ln⁡j!(ej57+∏p=1jΓ(p3))cos⁡(πj)+ej28\lim_{x \to \infty} \int_{-\infty}^{\infty} \frac{\prod_{n=1}^{\infty} \Gamma\left(\frac{\zeta(3) + n^2}{e^{\sin(\pi x)}}\right) \cdot \sqrt{\cosh\left(\ln\left(\frac{x^3}{\pi^2} + \sqrt[5]{n}\right)\right)}}{\sum_{k=1}^{\infty} \frac{\left(e^{k^{k!}} + \sin\left(\sqrt{\zeta(2)}\right)\right)^k}{\Gamma(k+1)}} \cdot e^{-\alpha x^2} dx = \sum_{j=1}^{\infty} \frac{\left(-1\right)^j \cdot \ln^{j!}\left(e^{\sqrt[7]{j^5}} + \prod_{p=1}^{j} \Gamma(p^3)\right)}{\cos\left(\frac{\pi}{j}\right) + \sqrt[8]{e^{j^2}}}
This is some straight up Retard fuel
 
just played it, i unironically prefer overwatch than boring capeshit characters
 

Similar threads

SeetheBot9000
Replies
19
Views
769
A.M.
A.M.
starystulejarz
Replies
19
Views
516
CroatianManlet2
CroatianManlet2
cockroach
Replies
3
Views
221
starystulejarz
starystulejarz
starystulejarz
Replies
5
Views
356
starystulejarz
starystulejarz
cockroach
Replies
4
Views
254
weaselbomber
weaselbomber

Users who are viewing this thread

shape1
shape2
shape3
shape4
shape5
shape6
Back
Top