Blackpill If you cant answer this question without looking it up youre incel becuase of your IQ

[Total Imbecile]

You might definitely be a lookscel but it doesnt matter because youre so low IQ that youre legally retarded

The number 2^29 has 9 digits, all different. Without computing 2^29, find the missing digit.

I couldnt solve it after thinking hard for an hour...

Do you guys notice how people usually treat you differently? I just realized that this is because Im a special needs

And no girls wants to date a retard, we just exist to help women virtue signal

 

[Deleted member 818]

I seriously don't even know what this is.

 

[Total Imbecile]

I seriously don't even know what this is.

Brutal, you cant even parse the question

 

[Deleted member 818]

Brutal, you cant even parse the question

I legit didn't study this shit in school.

 

[Total Imbecile]

I legit didn't study this shit in school.

Theres nothing to study tho, its an IQ question, you either know it or you dont

 

[wizardcel]

I have no idea if it's correct. I couldn't solve it without making any calculations.

2^29=9^x
log(2^29)=log9^x
29log2=xlog9
29log2=xlog3^2
29log2=2xlog3
29x0,30=6xlog3
8,7=2,88x
x=3.0

The missing digit is 3. I'm not sure if that's correct. Maybe they expect you to solve it using arithmetic sequence, but I don't remember high school math that well.

 

[Deleted member 1780]

29 mod 4 = 1, so the last digit is 2.

 

[Deleted member 1042]

IQ is cope. Just don’t be retarded.

 

[Total Imbecile]

29 mod 4 = 1, so the last digit is 2.

Its over, thats not even what the question is asking

 

[FlyFace]

I have no idea if it's correct. I couldn't solve it without making any calculations.

2^29=9^x
log(2^29)=log9^x
29log2=xlog9
29log2=xlog3^2
29log2=2xlog3
29x0,30=6xlog3
8,7=2,88x
x=3.0

The missing digit is 3. I'm not sure if that's correct. Maybe they expect you to solve it using arithmetic sequence, but I don't remember high school math that well.

How can your mind even comprehend that? My mind just snaps like a wafer anytime anything looks like that enters my head.

 

[Deleted member 1780]

Its over, thats not even what the question is asking

I'm getting closer. I eliminated one option.

The only way to get a 2 for the last digit is if the last digit of 2^28 is a 6 => the second to last digit of 2^29 is 1.

Right now I have:

xxxxxxx12

...

It is just a long chain of deduction.

 

[TheSecondComing]

didn't read but assuming that I won't.

 

[Legato]

I don't even know what the fucking question is asking lmao, or the relevancy to real world applications. Iq is cope anyway, doesn't stop sub 70 Chad from being successful.

 

[BlkPillPres]

I legit didn't study this shit in school.

Same

@Total Imbecile
You post doesn't make any sense, I never did history in school either, someone can just post something of common history and state the same thing - "you're low IQ if you don't know this"

Never even seen a question like this in all my years of schooling, you can't solve a problem if you haven't even been taught an algorithm
Also this:

or the relevancy to real world applications

You'll never used most of this shit in real life, still waiting for that magical real life scenario where I'll finally use Pythagoras Theorem to solve something

 

[Deleted member 20195]

Most normies won't be able to solve this. Alls I know is the last digit is even or 0.

 

[Total Imbecile]

Same

@Total Imbecile
You post doesn't make any sense, I never did history in school either, someone can just post something of common history and state the same thing - "you're low IQ if you don't know this"

Never even seen a question like this in all my years of schooling, you can't solve a problem if you haven't even been taught an algorithm

This is math though, unlike history math is legit and objective

Looking at the solution you literally just need addition and subtraction to answer this question, theres no complicated algorithm to solve it, just basic logic

If you know how to add and subtract numbers you wont get stuck if somebody gives you an expression like 2+(3+4) because by manipulating the numbers around you can easily derive the solution

 

[LastGerman]

21 = 2
22 = 4
23 = 8
24 = 16
25 = 32
26 = 64
27 = 128
28 = 256
29 = 512
210 = 1024
211 = 2048
212 = 4096
213 = 8192
214 = 16384
215 = 32768
216 = 65536
217 = 131072
218 = 262144
219 = 524288
220 = 1048576
221 = 2097152
222 = 4194304
223 = 8388608
224 = 16777216
225 = 33554432
226 = 67108864
227 = 134217728
228 = 268435456
229 = 536870912

 

[Dionysus]

jfl if you can't solve it

 

[Total Imbecile]

21 = 2
22 = 4
23 = 8
24 = 16
25 = 32
26 = 64
27 = 128
28 = 256
29 = 512
210 = 1024
211 = 2048
212 = 4096
213 = 8192
214 = 16384
215 = 32768
216 = 65536
217 = 131072
218 = 262144
219 = 524288
220 = 1048576
221 = 2097152
222 = 4194304
223 = 8388608
224 = 16777216
225 = 33554432
226 = 67108864
227 = 134217728
228 = 268435456
229 = 536870912

Youre not suppose to evaluate it

 

[Deleted member 1780]

Nvm what I was doing. It says you can't compute it.

 

[LastGerman]

Youre not suppose to evaluate it

 

[sub8male]

Shit looks like I’m a low iqcel.

 

[Deleted member 17997]

Shit looks like I’m a low iqcel.

rip all thos years of calculus tbh

 

[sub8male]

rip all thos years of calculus tbh

Tbh

 

[BlkPillPres]

theres no complicated algorithm to solve it, just basic logic

an algorithm is basic logic, but there's an "order" to it, a process, saying "you just have to add and subtract" doesn't mean anything, if you don't do it in the right order with the right numbers you won't get the correct answer, algorithm is just a term to define a series of logical steps, it doesn't inherently mean something complicated

We can abstractly simulate walking as an algorithm

BEGIN
  If "Standing"
      If Weight Is On "Left Foot"
          Move "Right Foot" Forward
          Shift Weight To "Right Foot"
      Else
          Move "Left Foot" Forward
          Shift Weight To "Left Foot"
END

To us, its "just walking", but there's always a series of steps involved, even if something has just two steps you can call it an algorithm, its part of a process

Saying "its just math" doesn't mean anything, what if someone was never thought to count, doing something as simple as 1+1 would be difficult at first because they don't know the process of addition

 

[Deleted member 1780]

2^29 = c1*10^0 + c2^10^1 + ... + c9^10^8, where {c1,c2...c9} are the 9 digits that comprise it.

2^29 mod 9 = (c1*10^0 + c2^10^1 + ... + c9^10^8) mod 9 = (c1 + ... + c9) mod 9 = 5.

We have :

(c1 + ... + c9) mod 9 = 5.

(c1 + ... + c9 ) mod 9 = ((9(9+1))/2 - k) mod 9 = 5 (By the sum up to n formula)



(9(9+1))/2 - k = 45 - k , so we need to find k such that:

(45 - k) mod 9 = 5.

41 mod 9 = 5 => k = 4



4 BABY! @Total Imbecile

 

[wizardcel]

OK. Forget everything I said before.

We're going to find the sum of the 9 digits. 1+2+3+4+5+6+7+8+9=45

We're looking for a single-digit number.

2^0=1
2^1=1
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=127
2^8=256
2^9=512
2^10=1024

I'm counting the first 10 digits. The problem says that there's a missing digit, so the total number of digits is 10.

Ok, we're nearly done. We have to find a single-digit number; we don't really want a decimal number. If we divide 45/3=15 ( it's a double digit number, so it's not our answer). Divide 45/5=9 and 45/9=5. Our highest digit is 9 and the smallest digit is 5. We want to find the missing digit. Therefore, 9-5=4

 

[Total Imbecile]

an algorithm is basic logic, but there's an "order" to it, a process, saying "you just have to add and subtract" doesn't mean anything, if you don't do it in the right order with the right numbers you won't get the correct answer, algorithm is just a term to define a series of logical steps, it doesn't inherently mean something complicated

We can abstractly simulate walking as an algorithm

BEGIN
  If "Standing"
      If Weight Is On "Left Foot"
          Move "Right Foot" Forward
          Shift Weight To "Right Foot"
      Else
          Move "Left Foot" Forward
          Shift Weight To "Left Foot"
END

To us, its "just walking", but there's always a series of steps involved, even if something has just two steps you can call it an algorithm, its part of a process

Saying "its just math" doesn't mean anything, what if someone was never thought to count, doing something as simple as 1+1 would be difficult at first because they don't know the process of addition

The whole point is that youre supposed to be able to come up with algorithms yourself tho

Thats what makes normies different from us, even if your algorithm is suboptimal you should be able to reason if youre 80+ IQ

Building on your example once you know how to walk you should be able to figure out how to climb stairs, even if youre a toddler and at first you just crawl up to reach the top

OK. Forget everything I said before.

We're going to find the sum of the 9 digits. 1+2+3+4+5+6+7+8+9=45

We're looking for a single-digit number.

2^0=1
2^1=1
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=127
2^8=256
2^9=512
2^10=1024

I'm counting the first 10 digits. The problem says that there's a missing digit, so the total number of digits is 10.

Ok, we're nearly done. We have to find a single-digit number; we don't really want a decimal number. If we divide 45/3=15 ( it's a double digit number, so it's not our answer). Divide 45/5=9 and 45/9=5. Our highest digit is 9 and the smallest digit is 5. We want to find the missing digit. Therefore, 9-5=4

HIGH IQ AF tbh

I dont understand but thats the correct answer, Im having trouble understanding the original solution too

 

[Deleted member 1780]

The whole point is that youre supposed to be able to come up with algorithms yourself tho

Thats what makes normies different from us, even if your algorithm is suboptimal you should be able to reason if youre 80+ IQ

Building on your example once you know how to walk you should be able to figure out how to climb stairs, even if youre a toddler and at first you just crawl up to reach the top


HIGH IQ AF tbh

I dont understand but thats the correct answer, Im having trouble understanding the original solution too

I gave a solution above.

 

[Total Imbecile]

2^29 = c1*10^0 + c2^10^1 + ... + c9^10^8, where {c1,c2...c9} are the 9 digits that comprise it.

2^29 mod 9 = (c1*10^0 + c2^10^1 + ... + c9^10^8) mod 9 = (c1 + ... + c9) mod 9 = 5.

We have :

(c1 + ... + c9) mod 9 = 5.

(c1 + ... c9 ) mod 9 = ((9(9+1))/2 - k) mod 9 = 5 (By the sum up to n formula)



(9(9+1))/2 - k = 45 - k , so we need to find k such that:

(45 - k) mod 9 = 5.

41 mod 9 = 5 => k = 4



4 BABY! @Total Imbecile

 

[ihaveno1]

????

 

[Total Imbecile]

I gave a solution above.

This question is from a book for quants, you could be easily making $400k+ with your IQ

I have to be happy making sub 6 figures I guess

 

[Deleted member 1780]

Key fact is this:

c10^n mod 9 = c mod 9

This question is from a book for quants, you could be easily making $400k+ with your IQ

I have to be happy making sub 6 figures I guess

I study math in college, and question is looks like competition math. It actually isn't a super hard question if you know about modulus.

The hard part is knowing that :

c*10^n mod 9 = c mod 9 ( 9 doesn't really matter actually).


here is an example

2*10 mod 9 = 2 mod 9 = 2
3*100 mod 9 = 3 mod 9 = 3
8*1000 mod 9 = 8 mod 9 = 8

 

[BlkPillPres]

The whole point is that youre supposed to be able to come up with algorithms yourself tho

Thats what makes normies different from us, even if your algorithm is suboptimal you should be able to reason if youre 80+ IQ

Dude you have literally zero ability to think abstractly, maybe its just you that's low IQ, all the "reasoning" that we as modern day humans can do IS AS A RESULT OF THE YEARS OF KNOWLEDGE BUILT UP BY PEOPLE BEFORE US

Pose this fucking question to a cave man before he is even aware of the concept of numbers, can he "just solve it", can he just "come up with algortihms", you literally lack the ability to think abstractly, its ridiculous, you don't seem to get that even the terms we are using (like "algorithm") only have meaning because we have the context and knowledge to understand it, you might as well say "you're supposed to be able to come up with zip zappers yourself tho"

Why did you use the word "algorithm", I mean if one is supposed to just be able to come up with something before being aware of concepts inherent to it, why are you using pre-established terminology, come up with new terminology then JFL, and then request that someone come up with solutions to that term that they don't know the meaning of, you might as well do that because you are essentially arguing that one should be able to do it

I'm done at this point, I doubt you even understand one thing I'm saying here and its going in one ear and out the other, you clearly can't understand what it is I'm arguing, because you can't think abstractly about anything really. To you numbers, counting, arithmetic, etc are just magically concepts that we are all just born aware of and innately know

Building on your example once you know how to walk you should be able to figure out how to climb stairs, even if you're a toddler and at first you just crawl up to reach the top

 

[Deleted member 16455]

I’m too low IQ

 

[Total Imbecile]

I doubt you even understand one thing I'm saying here and its going in one ear and out the other, you clearly can't understand what it is I'm arguing, because you can't think abstractly about anything really

This is why I will never lose my virginity, its over for me, I have the worst kind of malignant autism that one can have, Im not even the math/science/computer genius kind of autistic, Im literally just low iq autistic to the point where its probably hindering me more than my looks

The only difference between me and this guy:


is that I dont like noise and dont punch walls

 

[Deleted member 1780]

OK. Forget everything I said before.

We're going to find the sum of the 9 digits. 1+2+3+4+5+6+7+8+9=45

We're looking for a single-digit number.

2^0=1
2^1=1
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=127
2^8=256
2^9=512
2^10=1024

I'm counting the first 10 digits. The problem says that there's a missing digit, so the total number of digits is 10.

Ok, we're nearly done. We have to find a single-digit number; we don't really want a decimal number. If we divide 45/3=15 ( it's a double digit number, so it's not our answer). Divide 45/5=9 and 45/9=5. Our highest digit is 9 and the smallest digit is 5. We want to find the missing digit. Therefore, 9-5=4

Fellow mathcel.

 

[zangano1]

OK. Forget everything I said before.

We're going to find the sum of the 9 digits. 1+2+3+4+5+6+7+8+9=45

We're looking for a single-digit number.

2^0=1
2^1=1
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=127
2^8=256
2^9=512
2^10=1024

I'm counting the first 10 digits. The problem says that there's a missing digit, so the total number of digits is 10.

Ok, we're nearly done. We have to find a single-digit number; we don't really want a decimal number. If we divide 45/3=15 ( it's a double digit number, so it's not our answer). Divide 45/5=9 and 45/9=5. Our highest digit is 9 and the smallest digit is 5. We want to find the missing digit. Therefore, 9-5=4

I didnt understand shit

 

[Total Imbecile]

I study math in college, and question is looks like competition math. It actually isn't a super hard question if you know about modulus.

What year are you?

I still dont fully understand modulus and shit like fermats little theorem

Once you start taking mod of negative numbers or talking about its inverse I completely lose it

I dont know how I passed discrete math

 

[Deleted member 15737]

I failed arithmetic.

 

[Deleted member 1780]

What year are you?

I still dont fully understand modulus and shit like fermats little theorem

Once you start taking mod of negative numbers or talking about its inverse I completely lose it

I dont know how I passed discrete math

I'm close to graduation ngl. Just reread the definitions of everything if you're interested. Math is impossible to do if you don't know the definition & have a good foundation.

I remember failing middleschool math bc I wasn't interested, but I got an As in the grad level math courses I've take so far. Muh IQ didn't change, just motivation.

 

[BlkPillPres]

The only difference between me and this guy:

Dude what are you are you even saying right now lol, the guy in that video would not even be able to carry on the conversation we are having right now, he wouldn't even be able to pose the question you did much more answer it

The difference between you and him is huge

 

[78980n]

I'm assuming that's why you picked your username

 

[littlemanhikicel]

I don't understand that shit.

 

[Deleted member 19079]

tfw low iq and ethnic

 

[blond_elf_bard]

2^29 = c1*10^0 + c2^10^1 + ... + c9^10^8, where {c1,c2...c9} are the 9 digits that comprise it.

2^29 mod 9 = (c1*10^0 + c2^10^1 + ... + c9^10^8) mod 9 = (c1 + ... + c9) mod 9 = 5.

We have :

(c1 + ... + c9) mod 9 = 5.

(c1 + ... + c9 ) mod 9 = ((9(9+1))/2 - k) mod 9 = 5 (By the sum up to n formula)



(9(9+1))/2 - k = 45 - k , so we need to find k such that:

(45 - k) mod 9 = 5.

41 mod 9 = 5 => k = 4



4 BABY! @Total Imbecile

what is the mod operation, never learned that since the highest math I have completed is only Calc iI no linear algebra or abstract algebra or anything

 

[Deleted member 1780]

what is the mod operation, never learned that since the highest math I have completed is only Calc iI no linear algebra or abstract algebra or anything

"m mod n" is the remainder when m is divided by n.

modulo shows up a lot in abstract algebra: cyclic groups. Also number theory.

Cyclic group - Wikipedia

en.wikipedia.org

Reminds me of how much I hated abstract algebra...

 

[AntiPain]

now I feel worse

 

[Deleted member 18193]

Did you say you had to solve it just by thinking about it or using paper and pen?

 

[Deleted member 11159]

I can't do basic math bro