Calculate the frequency seperation ( in megahertz ) of the nuclear spin levels of a Carbon-13 isotope in a magnetic field of 15.4T given that it's mag

[Lookscel]

Solve plz

 

[Deleted member 22907]

do it yourself fagot

 

[TheSecondComing]

fuck off inel

 

[Hail The Bloatlord]

just accept your mortality and don't bother us with this shit

 

[nihility]

I wanted but fuck it

 

[Deleted member 21908]

Neutrino Factory beams are produced from muons decaying in a storage ring with long straight sections. Consider an ensemble of polarized negatively-charged muons. When the muons decay they produce muon neutrinos with a distribution of energies and angles in the muon rest–frame described by [33]:

d 2Nνµ dxdΩc.m. ∝ 2x 2 4π [(3 − 2x) + (1 − 2x)Pµ cos θc.m.] , (2) where x ≡ 2Eν/mµ, θc.m. is the angle between the neutrino momentum vector and the muon spin direction, and Pµ is the average muon polarization along the beam direction. The electron antineutrino distribution is given by: d 2Nν¯e dxdΩc.m. ∝ 12x 2 4π [(1 − x) + (1 − x)Pµ cos θc.m.] ,

d 2Nνµ dxdΩlab ∝ 1 γ 2 (1 − β cos θlab) 2 2x 2 4π [(3 − 2x) + (1 − 2x)Pµ cos θc.m.] , (4) and d 2Nν¯e dxdΩlab ∝ 1 γ 2 (1 − β cos θlab) 2 12x 2 4π [(1 − x) + (1 − x)Pµ cos θc.m.] . = cos/4 = it's over

 

[Disabledcel]

Neutrino Factory beams are produced from muons decaying in a storage ring with long straight sections. Consider an ensemble of polarized negatively-charged muons. When the muons decay they produce muon neutrinos with a distribution of energies and angles in the muon rest–frame described by [33]:

d 2Nνµ dxdΩc.m. ∝ 2x 2 4π [(3 − 2x) + (1 − 2x)Pµ cos θc.m.] , (2) where x ≡ 2Eν/mµ, θc.m. is the angle between the neutrino momentum vector and the muon spin direction, and Pµ is the average muon polarization along the beam direction. The electron antineutrino distribution is given by: d 2Nν¯e dxdΩc.m. ∝ 12x 2 4π [(1 − x) + (1 − x)Pµ cos θc.m.] ,

d 2Nνµ dxdΩlab ∝ 1 γ 2 (1 − β cos θlab) 2 2x 2 4π [(3 − 2x) + (1 − 2x)Pµ cos θc.m.] , (4) and d 2Nν¯e dxdΩlab ∝ 1 γ 2 (1 − β cos θlab) 2 12x 2 4π [(1 − x) + (1 − x)Pµ cos θc.m.] . = cos/4 = it's over

 

[Lookscel]

I wanted but fuck it

You can actually do it?

Neutrino Factory beams are produced from muons decaying in a storage ring with long straight sections. Consider an ensemble of polarized negatively-charged muons. When the muons decay they produce muon neutrinos with a distribution of energies and angles in the muon rest–frame described by [33]:

d 2Nνµ dxdΩc.m. ∝ 2x 2 4π [(3 − 2x) + (1 − 2x)Pµ cos θc.m.] , (2) where x ≡ 2Eν/mµ, θc.m. is the angle between the neutrino momentum vector and the muon spin direction, and Pµ is the average muon polarization along the beam direction. The electron antineutrino distribution is given by: d 2Nν¯e dxdΩc.m. ∝ 12x 2 4π [(1 − x) + (1 − x)Pµ cos θc.m.] ,

d 2Nνµ dxdΩlab ∝ 1 γ 2 (1 − β cos θlab) 2 2x 2 4π [(3 − 2x) + (1 − 2x)Pµ cos θc.m.] , (4) and d 2Nν¯e dxdΩlab ∝ 1 γ 2 (1 − β cos θlab) 2 12x 2 4π [(1 − x) + (1 − x)Pµ cos θc.m.] . = cos/4 = it's over

Wrong answer

 

[RollD20]

its over for relativitycels

 

[Blacktarpill]

I dont know man.

 

[Lookscel]

do it yourself fagot

fuck off inel

It's over

 

[nihility]

Yes I can lol

 

[MountainGorilla]

@MENSA_IQcel @BlkPillPres help OP

 

[SkinjobCatastrophe]

420.69 Hz

 

[ihaveno1]

No.

 

[Lookscel]

Yes I can lol

No you can't. Read the title.

420.69 Hz

Wrong answer

 

[Deleted member 21514]

No.

 

[nihility]

No you can't. Read the title.

Wrong answer

You need to post the full version

 

[Lookscel]

You need to post the full version

Nevermind it's a shitpost lol

 

[nihility]

Nevermind it's a shitpost lol

Shitposts me

 

[Deleted member 18214]

I dont know man.

 

[MENSA_IQcel]

Incomplete question, we need more information about its magnitude.

 

[Lookscel]

Incomplete question, we need more information about its magnitude.

It's a shitpost lol

 

[Yerberito]

I dont know man.