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Serious STEMcels help me out with this question

FidelCashflow

FidelCashflow

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I'm completely retarded tonight and cant figure out how to answer this question
 
I will be taking Physics II next semester so I can get back to you then
 
Not every STEM major is an electrician though.
 
You have to know the equation: E = VIT
E: Energy in Joules: 0.6 J
V: Potential Difference in Volts: 15 V
I : current in Amps: Unknown
t: time in seconds: 8 * 10^-6

Solve for I (Amps)
0.6 = 15 x I x 8 *10^-6

Current(i) is equal to 5000 Amperes or 5 kA
 
Power is the ratio between the variation in energy and the time it took to vary, so
P = 0.6 J / 8 us ,
P = 6.(10^-1) / (8).(10^-6). J / s ,
P = 6/8.(10^5) W, since W = J / s.

And the power associated to movement of electric charges can be decomposed like so:
P = dw / dt.
P = ( dw / dq ).( dq / dt ) , where:​
v(t) = dw / dq , and​
i (t) = dq / dt . Therefore:​
P = v(t) . i(t) , which gives:​
i(t) = P/v(t) .

So knowing v(t) and P, we have:
i(t) = 6/8.(10^5) W / 15 V ,
i(t) = 0.05.(10^5) W / V ,
i(t) = 5000 A., since W = V.A .
 
You have to know the equation: E = VIT
E: Energy in Joules: 0.6 J
V: Potential Difference in Volts: 15 V
I : current in Amps: Unknown
t: time in seconds: 8 * 10^-6

Solve for I (Amps)
0.6 = 15 x I x 8 *10^-6

Current(i) is equal to 5000 Amperes or 5 kA
Power is the ratio between the variation in energy and the time it took to vary, so
P = 0.6 J / 8 us ,
P = 6.(10^-1) / (8).(10^-6). J / s ,
P = 6/8.(10^5) W, since W = J / s.

And the power associated to movement of electric charges can be decomposed like so:
P = dw / dt.
P = ( dw / dq ).( dq / dt ) , where:​
v(t) = dw / dq , and​
i (t) = dq / dt . Therefore:​
P = v(t) . i(t) , which gives:​
i(t) = P/v(t) .

So knowing v(t) and P, we have:
i(t) = 6/8.(10^5) W / 15 V ,
i(t) = 0.05.(10^5) W / V ,
i(t) = 5000 A., since W = V.A .
Thanks for saving me frens. I would give you reddit gold if I could
 

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