FidelCashflow
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- Oct 7, 2019
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I'm completely retarded tonight and cant figure out how to answer this question
Lol this is first year electrical circuitsI will be taking Physics II next semester so I can get back to you then
ohLol this is first year electrical circuits
You have to know the equation: E = VIT
E: Energy in Joules: 0.6 J
V: Potential Difference in Volts: 15 V
I : current in Amps: Unknown
t: time in seconds: 8 * 10^-6
Solve for I (Amps)
0.6 = 15 x I x 8 *10^-6
Current(i) is equal to 5000 Amperes or 5 kA
Thanks for saving me frens. I would give you reddit gold if I couldPower is the ratio between the variation in energy and the time it took to vary, so
P = 0.6 J / 8 us ,P = 6.(10^-1) / (8).(10^-6). J / s ,P = 6/8.(10^5) W, since W = J / s.
And the power associated to movement of electric charges can be decomposed like so:
P = dw / dt.P = ( dw / dq ).( dq / dt ) , where:v(t) = dw / dq , andi (t) = dq / dt . Therefore:P = v(t) . i(t) , which gives:i(t) = P/v(t) .
So knowing v(t) and P, we have:
i(t) = 6/8.(10^5) W / 15 V ,i(t) = 0.05.(10^5) W / V ,i(t) = 5000 A., since W = V.A .