2
2
Nothing?
Should be same as square in lower left corner I think
2
I only solve this if I can krämpi afterwards
H
Solution=I can't breed
idk
My Asiatic IQ was suppressed by a brain lesion. This is why my older cousin has a degree in Sociology and I live on Disability payments.
I'll refer you to some useful sites:
puzzling.stackexchange.com
I'll refer you to some useful sites:
Puzzling Stack Exchange
Q&A for those who create, solve, and study puzzles
I can never figure these patterns out. Like wtf
I
Ok, it's solved. Now, explain why.
2
Sorry for shitty english it's my 3rd language.Ok, it's solved. Now, explain why.
Add the black cubes on the same side and subtract the white cubes on different sides of first 2 squares. then add them on the third square.
for example the first row square:adding the two cubes on the same side is 2, and subtracting the white cubes on differen sides is 1, then you have 2 black cubes and one white cube.(white cubes on third square go on the side where there is more white cubes, for for this is the left side which has 3 white cubes.)
do the same for the second row:adding the black cubes on the same side is zero so no black cubes,subtracting the white cubes on different sides is 1 so there's only 1 white cube one the side which has more white cubes(right one).
now for the third row there is no white cube so subtracting them is 0 obviously
. and 2 black cubes,adding them is 2 black cubes on left like this pic:
Too bad my brain can't fucking stand solving shit like that.
That is too convoluted for me to understand right now.Sorry for shitty english it's my 3rd language.
Add the black cubes on the same side and subtract the white cubes on different sides of first 2 squares. then add them on the third square.
for example the first row square:adding the two cubes on the same side is 2, and subtracting the white cubes on differen sides is 1, then you have 2 black cubes and one white cube.(white cubes on third square go on the side where there is more white cubes, for for this is the left side which has 3 white cubes.)
do the same for the second row:adding the black cubes on the same side is zero so no black cubes,subtracting the white cubes on different sides is 1 so there's only 1 white cube one the side which has more white cubes(right one).
now for the third row there is no white cube so subtracting them is 0 obviously
Brain not working
2
Ok my explanation was confusing as fuck here's a more compact one:That is too convoluted for me to understand right now.
Formula:For each row, if cubes of same color on the first two squares are on the same side(right and left sides.), add them,then put them on the third square.if they are not on the same side,subtract them and put them the third square on the side where there were more squares.
solving 1st row:for black cubes in frst 2 squares are on the same side(both left) so by adding them we have 1+1=2 so 2 black cubes on the third square.white cubes are on diferent sides,so subtracting them 3-2=1 and putting them on third square we have 1 white cube and 2 black cubes.
do it for next two rows.
am i retarded
No, even the explanation put up is kinda confusing
but also
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