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Serious Mathcel championship, question for high iq mathcels

DostoevskyCel

DostoevskyCel

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Screenshot 2021 06 02 at 113120


if this post gets any traction I'd like to make it a weekly thing, basically I post a (typically number theory, but will include geometry and single variable calc, and you don't need to answer all the questions I post) question and people post their solutions, after about a day or so I'll post my solution. First week's problem is above and below are my hints for my solution, the hints get progressively bigger:
hint 1: without loss of generality suppose a >= b >= c
hint 2: use inequalities to find an upper bound of one of the variables
hint 3: if c is the smallest of the ordered solution a, b, c, then (1+ 1/c) is the largest factor, hence 2 =< (1 + 1/c)^3
 
we already did this. it was pinned on the lounge and it was really cool


i don't really know too much number theory so i dunno
 
Nooooooo you can't make me construct a domain of possible values this early :feelsree::feelsree::feelsree::feelsree:
 
holy shit i got it but my ''proof'' isn't elegant lol

<a=2, b=15, c=4> ; <a=2, b=9, c=5> ; <a=2, b=7, c=6> ; <a=3, b=5, c=4> ; <a=3, b=3, c=8>

When are you posting the proof? I've never done number theory yet, I graphed and checked myself for the values of b with bounds. I have absolutely no idea how you would do this algebraically.
 
Do ur own homework, GrAYcel
 
holy shit i got it but my ''proof'' isn't elegant lol

<a=2, b=15, c=4> ; <a=2, b=9, c=5> ; <a=2, b=7, c=6> ; <a=3, b=5, c=4> ; <a=3, b=3, c=8>

When are you posting the proof? I've never done number theory yet, I graphed and checked myself for the values of b with bounds. I have absolutely no idea how you would do this algebraically.
ive not done number theory either, uk maths curriculum is extremely regimented, I pick up most my techniques from youtubers, ill post in soonish, algebraically is a bit of a misnomer here tho, I used algebra to get an upper bound and then went thru the few cases the bound provides
Do ur own homework, GrAYcel
my college has finished for the year + I had already done it when I posted this question
5EC81AEB 735C 423D 8998 41B1C1462BF1

A40782F4 17C0 4566 9F25 9FA81A7F321E

A591766C 1B7E 46F6 B08D D8F610CB90B1

@registeredsubhuman9
 
Last edited:
I miss being good at maths. I'm scratchy as hell now.
 
Wow you guys are high IQ ngl
 
ive not done number theory either, uk maths curriculum is extremely regimented, I pick up most my techniques from youtubers, ill post in soonish, algebraically is a bit of a misnomer here tho, I used algebra to get an upper bound and then went thru the few cases the bound provides

my college has finished for the year + I had already done it when I posted this question
View attachment 451849
View attachment 451850
View attachment 451851
@registeredsubhuman9
Nice solution bruh. Never could have thought of doing it this way.
I miss being good at maths.
 
@trying to ascend

This may offer you some enjoyment.
 

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