SuicideFuel Problem

[trying to ascend]

[UWSL]Consider an arithmetic progression (AP) of integers with a ratio p > 2, its first term greater than 2 and its last term less than 47. Removing a certain number of elements from the AP, one falls into a PG of 3 elements and ratio q > 2. For p and q integers, p different from q, determine the PA whose sum of its elements is the largest possible.[/UWSL]

[UWSL][/UWSL]

 

[Lolimancer]

10

 

[InMinecraft]

10

nope, the exact answer is: 56,63467444456764446677655568906311123456777, I used only my mind without a calculator