3!(x - 1)!/4(x - 3)! = 182(x - 2)! - x!/2(x - 2)!
x belonging to the natural numbers, the solution is?
x belonging to the natural numbers, the solution is?
¡Y!
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8
You can simplify it until it becomes 2x^2 - 5x = 88 which is 8
6(x-1)! = 6(x-1)(x-2)(x-3)! simplify with its divisor and left side of the equation becomes (3(x-1)(x-2))/2
Multiply both sides by 2
3(x-1)(x-2) = (182 (x-2)! -x!)/(x-2)!
which becomes
182 - x(x-1) on the right side
which becomes
3x^2 + 6 - 9x = 182 -x^2 + x
which is
2x^2 -5x = 88 which gives you the result 8
Sleepy as fuck might have fucked up a bit writing shit here but overall that's yeah
You can simplify it until it becomes 2x^2 - 5x = 88 which is 8
6(x-1)! = 6(x-1)(x-2)(x-3)! simplify with its divisor and left side of the equation becomes (3(x-1)(x-2))/2
Multiply both sides by 2
3(x-1)(x-2) = (182 (x-2)! -x!)/(x-2)!
which becomes
182 - x(x-1) on the right side
which becomes
3x^2 + 6 - 9x = 182 -x^2 + x
which is
2x^2 -5x = 88 which gives you the result 8
Sleepy as fuck might have fucked up a bit writing shit here but overall that's yeah
Last edited:
Correct
B
42
Wrong
B
Right
I
I think 8, but not because someone else has already written the answer in this thread, nono
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