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SuicideFuel Problem

trying to ascend

trying to ascend

Oldcel KHHV
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In a lottery, three distinct numbers are raffled out of 12 possible numbers.

If a ticket containing three numbers costs 2R$, then how much a ticket containing 5 numbers costs?
 
Last edited:
This is not a problem.
Inceldom is a problem
 
I don't understand the question.
"three distinct numbers are raffled"
Does this mean there are 3 winners?
Or that there is one winner and he has to have all 3 numbers?
 
I don't understand the question.
"three distinct numbers are raffled"
Does this mean there are 3 winners?
Or that there is one winner and he has to have all 3 numbers?
Yes, three distinct numbers are randomly chosen, the winner is the guy that also chose those 3 numbers
 
12x12x12 = 1728 possible outcomes
3 number ticket = 1 possible outcome
5 number ticket = 5*4*3 = 60 possible outcomes
I guess it should be 60*2 = 120R$
 
12x12x12 = 1728 possible outcomes
3 number ticket = 1 possible outcome
5 number ticket = 5*4*3 = 60 possible outcomes
I guess it should be 60*2 = 120R$
Distinct numbers bhai
 
Distinct numbers bhai
:feelsUgh:

I'm too dumb. From internet calculator this is the possible combinations of 3 numbers from 5 numbers:

1650129418524


So it should be 10R$
 

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